this post was submitted on 02 Dec 2024
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xkcd

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The growth rate of items per day may may seem absurd, but it's actually much less than the acceleration in the 12 Days of Christmas song.

https://explainxkcd.com/3019/

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[–] ininewcrow@lemmy.ca 15 points 3 weeks ago (2 children)

What if you the advent calendar you open, opens another advent calendar, which opens another advent calendar and another and another without end?

[–] wildflower@lemmy.world 9 points 3 weeks ago

Hilbert's advents calendar

[–] Hamartiogonic@sopuli.xyz 7 points 3 weeks ago (3 children)

Infinite calendarception… but do you get any chocolate in this setup?

[–] ininewcrow@lemmy.ca 4 points 3 weeks ago (1 children)
[–] Hamartiogonic@sopuli.xyz 2 points 3 weeks ago (1 children)

Sure, no problem. That’s only going to take an infinite amount of time, so we’re all good.

[–] ininewcrow@lemmy.ca 3 points 3 weeks ago (1 children)

Think of the chocolate at the end tho

[–] Hamartiogonic@sopuli.xyz 2 points 3 weeks ago

There is no end. Kinda essential part of the definition of infinity.

[–] Iron_Lynx@lemmy.world 4 points 3 weeks ago

Depends on the final advent calendars. I've seen one where the final product is an electric screwdriver, with screw bits and all.

[–] murmelade@lemmy.ml 3 points 3 weeks ago (1 children)

Only on Sundays but you get infinite chocolates.

[–] Hamartiogonic@sopuli.xyz 2 points 3 weeks ago

Fair enough, as long as it’s a countably infinite amount of chocolate.

[–] Mammothmothman@lemmy.ca 9 points 3 weeks ago (1 children)
[–] jungle@lemmy.world 3 points 3 weeks ago* (last edited 3 weeks ago)

I like explainers, so I want an explainer for the explainer.

No, really, I need an explainer for the explainer. I got lost mid way through...

[–] FilthyShrooms@lemmy.world 6 points 3 weeks ago (2 children)

So assuming 25 advent calenders in the advent calender, each with the correct amount of days (1st has 25, 2nd has 24, etc), how many chocolates would there be in total?

[–] Tudsamfa@lemmy.world 13 points 3 weeks ago (1 children)

(n*(n+1)/2 = 25*13 =325

Never mind the fact that the "correct" number of days on an advent calender is 24.

[–] Iron_Lynx@lemmy.world 2 points 3 weeks ago (1 children)

For one, it looks to me like the triangle numbers, which for triangle number T~n~ = (n+1) choose 2.

So for a correct nested advent calendar of 24 days, it's T~24~ = (24+1) choose 2 = 300

[–] Iron_Lynx@lemmy.world 2 points 3 weeks ago* (last edited 3 weeks ago)

Also, it appears that they created the terminal function that does that in a very compact notation, so another correct way to write down this sum is "24?" Where n? = n + (n-1)?

[–] SwordInStone@lemmy.world 2 points 3 weeks ago

primary school combinatorics question

[–] AwesomeLowlander@sh.itjust.works 1 points 3 weeks ago (1 children)

Could we link the actual image instead of the external site? For example, in today's comic the bottom line of text was cleanly cut out of the thumbnail, and it looked like it was complete (and even made grammatical sense).

[–] schnurrito@discuss.tchncs.de 6 points 3 weeks ago (1 children)

No idea what problem you're talking about, doesn't occur the way I view it. You are in any case free to do that when you are the first person to post a new xkcd here; I will continue to link to the comic page because people might want to browse other things on the xkcd website from it.

Depends a lot on which client you use to browse lemmy, I'm sure. Not everybody will experience it of course. Thank you anyway for your efforts in posting daily :)