this post was submitted on 16 May 2024
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[–] Abnorc@lemm.ee 30 points 4 months ago (6 children)

Almost. 1/x approaches infinity from the positive direction, but it approaches negative infinity from the negative direction. Since they approach different values, you can't even say the limit of 1/x is infinity. It's just undefined.

[–] NeatNit@discuss.tchncs.de 6 points 4 months ago (4 children)

https://en.wikipedia.org/wiki/Division_by_zero#Floating-point_arithmetic

In IEEE arithmetic, division of 0/0 or ∞/∞ results in NaN, but otherwise division always produces a well-defined result. Dividing any non-zero number by positive zero (+0) results in an infinity of the same sign as the dividend. Dividing any non-zero number by negative zero (−0) results in an infinity of the opposite sign as the dividend. This definition preserves the sign of the result in case of arithmetic underflow.

[–] Bumblefumble@lemm.ee 0 points 4 months ago (3 children)

10/0 ≠ lim x->0+ 10/x

Or in other words, the thing you keep quoting does not apply in this case. Any number divided by zero is undefined, not positive infinity (or negative infinity for that matter).

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